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August 29, 2014

August 29, 2014

Posted by **unknown** on Thursday, August 23, 2007 at 11:04pm.

- Algebra1 -
**DrBob222**, Thursday, August 23, 2007 at 11:07pmSubstitute 2x+1 into equation 1 for y and solvee for x.

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 11:08pmhuh??

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 11:11pmx-3(2x+1)=?

since y=2x+1

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 11:28pmx-3y=8 and y=2x+1, then x= ???

- Algebra1 -
**Marie**, Saturday, September 1, 2007 at 2:15pmif x-3y=8 and y=2x+1, then x=

- Algebra1 -
- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 11:30pmx-3(2x+1)=??

you have to solve it by multiplying the 3 over and then just adding the x's and the #'s without the x's

Nobody's going to give you all the answers.

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 11:47pmim not asking for da answer I juss dont know how to do it.... im confussed....

so i multiply the 3&1 ( right??)

then i add the #'s with x's... 1x + 2x which is 3x^2.... see i dont know wat im doing.... becasue the multiply choices are single digits or fractions....

- Algebra1 -
**~christina~**, Friday, August 24, 2007 at 12:00amwell

x-3(2x+1)=

multiply the -3 and the 2x+1

then add

- Algebra1 -
**unknown**, Friday, August 24, 2007 at 8:51pmthank u..... & sorry if i was rude... i was just confused...

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