Posted by unknown on Thursday, August 23, 2007 at 10:24pm.
i think i have to simplify.... but the question just says:
(2y3)^2
possible answers:
a.4y^2+9
b.4y^26y+9
c.4y^212y+9
d.4y^2+12y+9

Algebra1  ~christina~, Thursday, August 23, 2007 at 10:44pm
separate and multiply based on
FOIL
first
outer
inner
last
(2y3)^2=
(2y3)(2y3) then use foil and multiply the first term, outer term, inner terms then last terms .
(2y3)(2y3)
first terms multiplied
2y*2y= 4y^2
outer terms multiplied
2y*(3)=6y
inner terms multiplied
(2y)*3=6y
last terms multiplied
(3)*(3)=9
Now combined FOIL (first outer inner and last terms )
4y^26y6y+9= but now you can combine the 6y's so (6y6y=12y)
and you get 4y^212y+9

Algebra1  unknown, Thursday, August 23, 2007 at 10:57pm
thank you...

Algebra1  ~christina~, Thursday, August 23, 2007 at 11:05pm
Your welcome =)

Algebra1  DrBob222, Thursday, August 23, 2007 at 10:45pm
duplicate post

Algebra1  ~christina~, Thursday, August 23, 2007 at 10:47pm
inner terms multiplied
2y*(3)=6y
it is the same as the outer terms multiplied (the negative was misplaced before)

Algebra1  ~christina~, Thursday, August 23, 2007 at 10:48pm
Oh..it was a duplicate?
Oh well I solved it Dr.Bob.=D
anyways..ha
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