Algebra1
posted by unknown .
i think i have to simplify.... but the question just says:
(2y3)^2
possible answers:
a.4y^2+9
b.4y^26y+9
c.4y^212y+9
d.4y^2+12y+9

separate and multiply based on
FOIL
first
outer
inner
last
(2y3)^2=
(2y3)(2y3) then use foil and multiply the first term, outer term, inner terms then last terms .
(2y3)(2y3)
first terms multiplied
2y*2y= 4y^2
outer terms multiplied
2y*(3)=6y
inner terms multiplied
(2y)*3=6y
last terms multiplied
(3)*(3)=9
Now combined FOIL (first outer inner and last terms )
4y^26y6y+9= but now you can combine the 6y's so (6y6y=12y)
and you get 4y^212y+9 
thank you...

Your welcome =)

duplicate post

inner terms multiplied
2y*(3)=6y
it is the same as the outer terms multiplied (the negative was misplaced before) 
Oh..it was a duplicate?
Oh well I solved it Dr.Bob.=D
anyways..ha