Posted by **unknown** on Thursday, August 23, 2007 at 10:24pm.

i think i have to simplify.... but the question just says:

(2y-3)^2

possible answers:

a.4y^2+9

b.4y^2-6y+9

c.4y^2-12y+9

d.4y^2+12y+9

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 10:44pm
separate and multiply based on

FOIL

first

outer

inner

last

(2y-3)^2=

(2y-3)(2y-3) then use foil and multiply the first term, outer term, inner terms then last terms .

(2y-3)(2y-3)

first terms multiplied

2y*2y= 4y^2

outer terms multiplied

2y*(-3)=-6y

inner terms multiplied

(-2y)*3=-6y

last terms multiplied

(-3)*(-3)=9

Now combined FOIL (first outer inner and last terms )

4y^2-6y-6y+9= but now you can combine the -6y's so (-6y-6y=-12y)

and you get 4y^2-12y+9

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 10:57pm
thank you...

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 11:05pm
Your welcome =)

- Algebra1 -
**DrBob222**, Thursday, August 23, 2007 at 10:45pm
duplicate post

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 10:47pm
inner terms multiplied

2y***(-3)**=-6y

it is the same as the outer terms multiplied (the negative was misplaced before)

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 10:48pm
Oh..it was a duplicate?

Oh well I solved it Dr.Bob.=D

anyways..ha

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