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October 2, 2014

October 2, 2014

Posted by **unknown** on Thursday, August 23, 2007 at 9:51pm.

- Algebra1 -
**DrBob222**, Thursday, August 23, 2007 at 9:55pmSo what is to be done?

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 9:59pmit is in fraction form & i have to solve i guess.... the mutipul choice answers are as follows in fraction form:

a. x/10

b.3x/10

c.17x/20

d.33x/20

please help me....

- Algebra1 -
**~christina~**, Thursday, August 23, 2007 at 10:06pmgo and

find the lowest common denominator between the 4, 5 and 2

a common multiple is 20 so..

3x/4 - 2x/5 +x/2=

5(3x/20)- 4(2x/20) + 10(x/20)=

then multiply ...

15x/20 - 8x/20 + 10x/20=__________ ???

now add and what do you get?

- Algebra1 -
**DrBob222**, Thursday, August 23, 2007 at 10:06pmIf the equation is:

(3x/4) - (2x/5) + (x/2)

Common denominator is 20

(15x/20) - (8x/20) + (10x/20) =

combine the three to obtain

17x/20

- Algebra1 -
**unknown**, Thursday, August 23, 2007 at 10:12pm~*THANKS*~

- Algebra1 -
**17x+5=-3(4)**, Wednesday, December 15, 2010 at 5:04pm17x+5=-3(4)

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