Posted by kate on Wednesday, August 22, 2007 at 5:05am.
I'n not sure I fully understand your question, but let me take a stab.
The likelyhood of a care being warranted and registered is 80%*%90 = 72 = 0.72 Ergo, the likelyhood of having a problem is 0.28
So, with 50 cars you would expect to find .28*50=14 problem cars, with a standard deviation of sqrt(.28*.72*50)=3.17
Take it from here. I hope this helps.
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