Thursday

July 31, 2014

July 31, 2014

Posted by **Sarah** on Tuesday, August 21, 2007 at 7:23pm.

3sqrt5y^5 divided by 6sqrt20xy

For this

3 square root 5y^5

___________________

6 square root 20xy

you can reduce the 3/6 to 1/2

then you can go and split up the bottom denominator of square root 20 into square root of 5y * square root of 4x and cancel out the sqrt 5y on both top and bottom ...remembering to subtract the y's when dividing the top by the bottom and thus subtracting the larger power y from the lower power y on the bottom getting y^4 on the top.

then you'd have:

(y^4/ sqrt 4x)(1/2) then get

y^4/4

That's it I think

For this

3 square root 5y^5

___________________

6 square root 20xy

you can reduce the 3/6 to 1/2

then you can go and split up the bottom denominator of square root 20 into square root of 5y * square root of 4x and cancel out the sqrt 5y on both top and bottom ...remembering to subtract the y's when dividing the top by the bottom and thus subtracting the larger power y from the lower power y on the bottom getting y^4 on the top.

then you'd have:

(y^4/ sqrt 4x)(1/2) then get

y^4/4

That's it I think

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