20 x+3(y-1)=11
2(x-y)+8y = 28
multiply out
20 x+3y-3=11 - Is this correct?
2x+14y = 28
Using the addition method, would you multiply the first problem by 2 and the second by 20?
No. In the second multiply out, you should have gotten
2x -1y+8y=28 or
2x+7y=28
No, in the addition method
20x+3y=14
2x+14y=28
multiply the second equation by ten, then subtract one from the other.
Bob, I read the questions as
x+3(y-1)=11 ------> x+3y = 14 and
2(x-y)+8y = 28----> 2x-2y+8y=28 or x+3y=14
which are two identical equations.
I think the 20 was the question number.
You are correct. The first equation simplifies to x + 3y = 14, and the second equation simplifies to x + 3y = 14 as well. These two equations are identical, which means they represent the same line on a graph and have infinitely many solutions.
You are correct, my apologies for the confusion. The correct simplified equations are:
x + 3(y - 1) = 11 -> x + 3y = 14
2(x - y) + 8y = 28 -> 2x - 2y + 8y = 28 -> 2x + 6y = 28
Upon simplifying, we can see that both equations are the same, which means they represent the same line. This implies that the system of equations has infinitely many solutions.