Posted by **Marissa** on Sunday, August 19, 2007 at 9:15pm.

how would you solve this;

Write an equation for the hyperbola with vertices (-10,1) and (6,1) and foci (-12,1)and (8,1)

The centre is the midpoint between the vertices, which is ((-10+6)/2,(1+1)/2) or (-2,1)

so the equation looks like

(x+2)^2/a^2 - (y-1)^2/b^2 = 1

a is the distance from the centre to the vertex, so a = 8

c is the distance between the centre and the focal point, so c = 10

In a hyperbola a^2 + b^2 = c^2

so 64 + b^2 = 100

b^2 = 36

your equation would be

(x+2)^2/64 - (y-1)^2/36 = 1

## Answer This Question

## Related Questions

- Algebra 2 - Choose the equation that best represents an ellipse for the given ...
- Maths - Find the equation, Centre, vertices, co-vertices, foci, equations of ...
- Maths - Find the equation, Centre, vertices, co-vertices, foci, equations of ...
- Algebra II-Please check - I'm sorry the computer jammed on an earlier post and I...
- Math/ Algebra - Find an equation for the hyperbola described: 1) Vertices at (0...
- math - the vertices are at (2,1) and (2,7) and focus is at (2,*) write the ...
- algebra 2 - Graph the equation. Identify the vertices, foci, and asymptotes of ...
- algebra - Write an equation of the hyperbola with foci (0, ) and (0, 2) and ...
- algebra 2 - Write an equation of the hyperbola with vertices at (–7, 0) and (7, ...
- algebra 2 - Write an equation of the hyperbola with foci (0, -2) and (0, 2) and ...

More Related Questions