Posted by PHYSICS on .
White light strikes a diffraction grating (930 lines/mm) at normal incidence. What is the longest wavelength that forms a secondorder maximum?
I used the equation [(1/d)sin(90)]/m = wavelength: [(1/0.93m)(1)] /2 = 0.5376m. To convert to nm I multiplied by 10^9. This is incorrect. Can anyone help? Thanks
Isn't d the reciprocal of 930/mm? or
or 1/d= .001m/930=1.08E8 m or .108nm?
check my thinking. In your equation, unit wise, if you are to have length on the right, you have to have length units on the left.
I remember the grading equation as
d sinTheta /n= lambda, where d is in meters.
Perhaps that is your error.

micole 
Jonathon,
The answer should follow such that
Lines/mm > d > (1/930mm)/1000mm/m
d = 1.075e6 meters
set sin theta = 90o = (1)
(dsin(Theta))m=mlambda
(1.075e6 (1))/2)= 5.375e7 or 537nm.