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October 22, 2014

October 22, 2014

Posted by **Dee** on Sunday, August 19, 2007 at 4:19pm.

I have worked to this point and now I'm stuck.

2(x-3)/7 * 4/5(x-5) and I don't know where to go from here. Can anyone point me in the right direction?

No. the second term in th denominator factors to 5(x-3), which then will divide into the numerator.

I think what you have should be....

[2(x-3)/7] * [4 / (5*(x-3)) ]

then cancel out the (x-3) ' s

and then you should get 8/35

sorry i somehow always end up posting my suggestions after bob

i guess i type too slow :)

- math/algebra -
**joyce**, Sunday, September 16, 2007 at 3:42pm9/x-5-1=8/x+5

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