can someone check my work?
x^2 = 22
x�ãx-22
if x^2 is 22, then x is +- sqrt 22
To solve the quadratic equation x^2 = 22, you can take the square root of both sides.
√(x^2) = √(22)
Since the square root can have both positive and negative solutions, we have two cases:
Case 1: Positive solution:
x = √(22)
Case 2: Negative solution:
x = -√(22)
Now, let's check your work for the second equation x�ãx-22:
To check if x^2 = 22 satisfies the equation x�ãx-22, we substitute the values of x into the equation and see if it holds true.
For the positive solution x = √(22):
√(22) * √(22) - √(22) - 22
= 22 - √(22) - 22
= - √(22)
For the negative solution x = -√(22):
-√(22) * -√(22) - (-√(22)) - 22
= 22 + √(22) - 22
= √(22)
It looks like you made an error in your calculation. The correct equation x�ãx-22 would be:
x^2 - x - 22
I would recommend revisiting the problem and double-checking your work.