Wednesday

August 20, 2014

August 20, 2014

Posted by **Jodi** on Thursday, August 16, 2007 at 10:25pm.

Please help!

Let x be the triangle's side length and y be the square's side length.

3x = 4y + 7

x = y + 5

Solve those two simultaneous equations. One way would be to substitute y+5 for x in the first equation. This would give you

3y + 15 = 4y + 7

which leads to y=8 etc.

3

- Algebra -
**Anonymous**, Saturday, September 8, 2012 at 7:02pmside of the triange is 20 while side of the square is 15

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