Tuesday

September 2, 2014

September 2, 2014

Posted by **DrBob222** on Thursday, August 16, 2007 at 10:21pm.

Then #2 = x+1

#3 = x+2

#4 = x+3

The problem says we want the sum of the first three. That will be

x + (x + 1) + (x + 2) and that should be 60 more than the fourth. The fourth is x + 3; therefore, set them equal and add 60 to the fourth. Solve for x.

Post your work if you get stuck.

x+(x+1)+(x+2) = (x+3)+60

Find four consecutive integers such that the sum of the first three is 60 more than the fourth.

What is the best way to solve this?

**Answer this Question**

**Related Questions**

College Algebra - The sum of two numbers is less than 12. The second number is 8...

Math - Find three consecutive integers such that the sum of the first and second...

Calculus - The problem I have is a summation from 1 to infinity for (-1)^n/n. I ...

Algebra (Integer Problem) - The sum of three positive numbers is 33. The second ...

Math - Help pls! I just need to set the equations only, I can do the rest. The ...

Math 130 - Sum the first two odd numbers, then the first three, the first four...

math sequences and series - how do i solve the sum of the first two terms of an ...

math-a-matic - okay...is this even possible? because i've tried every way i can ...

algebra 2 - An arithmetic progression has 5 terms that have a sum of 200. The ...

SUMS? - what is the sum of the first towo odd numbers? what s the sum of the ...