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January 30, 2015

January 30, 2015

Posted by **JaredN1** on Monday, August 13, 2007 at 2:57am.

PQR x 3 = QQQ

3xPQR = QQQ = Qx111 ---->

PQR = 37 Q ---->

P0R = 27 Q

You know that 25x4 = 100, so you could try Q = 4, beause you ten get a number slightly larger than 100 which will probably have a zero as the second digit:

27 x 4 = 108

So, Q = 4 and we see that P = 1 and

R = 8.

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