Thursday

July 24, 2014

July 24, 2014

Posted by **Marissa** on Sunday, August 12, 2007 at 11:24pm.

answer=y=-3/2(x+8)^2+4

2)Solve x^2>_2x+24

answer=x<_-4 or x>_6

1)Write an equation for the parabola whose vertex is at (-8,4) and passes through (-6,-2)

answer=y=-3/2(x+8)^2+4

2)Solve x^2>_2x+24

answer=x<_-4 or x>_6

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