Posted by **Tashanna** on Saturday, August 11, 2007 at 4:07pm.

How many different 5- member committees can be formed from 9 students?

A.24 B.126 C.15,120 D.362880

9!/(5!*4!)

1*2*3*4*5*6*7*8*9/[(1*2*3*4*5)(1*2*3*4)]

= 6*7*8*9/(1*2*3*4)

=126

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