State the possible number of imaginary zeros of g(x)= x^4+3x^3+7x^2-6x-13

this is how far Ive gotten:there are 4 zeros,3 positive and 1 negative

If you've found four real zeroes, then there are no imaginary zeroes. You can also see that there are no imaginary zeroes directly:

Put x = i y in the equation:

y^4 - 3iy^3 - 7y^2- 6iy - 13 = 0

Equate real and imaginary parts to zero:

y^4 - 7 y^2 - 13 = 0

And:

y^3 + 2 y = 0

The last equation has only one solution:

y = 0

But this does not satisfy the first equation.

so what is the answer? my choices are A)3 or 1
B)2,4,0
c)exactly 1
d)exactly 3
is it B?

Yes, the answer is B

I think it's B. Good luck!

Yes, the answer is B) 2, 4, 0.

To find the possible number of imaginary zeros, you need to determine the number of non-real or complex zeros.

In the given polynomial function g(x) = x^4 + 3x^3 + 7x^2 - 6x - 13, you have already determined that there are 4 zeros, 3 positive and 1 negative. However, this information pertains to the real zeros of the function.

To find the complex zeros, you can use the Fundamental Theorem of Algebra, which states that a polynomial of degree n will have exactly n complex zeros, including repeated zeros. Since the degree of the given function is 4, it can have at most 4 complex zeros.

Since you have already found 4 real zeros, you can conclude that there are no imaginary zeros. Therefore, the correct answer is B) 2, 4, 0, indicating that there are 2 complex zeros and 0 imaginary zeros.