Posted by **charlie** on Friday, August 10, 2007 at 2:06pm.

given: 1st derivative is

2(2-3x-2x^2)/(1+x^2)^2 (quotient rule)

I've found the stationary points to be x=1/2 and x=-2

Am I on the right track?

If so, I plan to plug in values to the L andR of them into the whole derivative so as to clasify them. Still on track?

Thanks

those are the correct values of x where the derivative is zero.

I don't know what you mean by the second part.

Thanks for the confirmation: The second part refers to deciding whether the zero points are minima or maxima.

## Answer This Question

## Related Questions

- Differentiation - Again, that all makes sense. Thank you very much. Thank you ...
- Calculus,Stationary Points,First derivative test - Good afternoon, I need a bit ...
- Please check my Calculus - 1. Find all points of inflection of the function f(x...
- Please check my Calculus - 1. Find all points of inflection of the function f(x...
- MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...
- Applied Calculus - Find the first and second derivative of the function: x/(7x+...
- 12th Grade Calculus - Find d^2y/dx^2 by implicit differentiation. x^(1/3) + y^(1...
- calculus - relative extrema x^3 + 1/2x^2 - 2x + 5 Ok I have 3x^2 + x - 2 = 0 Am ...
- Calculus - For y=(1/4)x^4-(2/3)x^3+(1/2)x^2-3, find the exact intervals on which...
- Calculus - y= ln3x *e^2x^2 + sin5x^2 find the derivative. i know what to do. but...

More Related Questions