find f(x) = –x3 + x2 + 2x + 7, find f(–3), f(0), and f(2)
Wouldn't you just substitute the value of x (-3, or 0, or 2) into the equation and compute?
Can you just show me how to do the first one....my brain is fried at this point
Yes, you're correct! To find the value of f(x) for a given value of x, you simply substitute that value into the equation and compute the result.
Let's start with f(–3). We have the equation f(x) = –x^3 + x^2 + 2x + 7. To find f(–3), substitute –3 for x in the equation:
f(–3) = –(–3)^3 + (–3)^2 + 2(–3) + 7
Now, let's simplify the equation step by step:
f(–3) = –(–27) + 9 – 6 + 7
= 27 + 9 – 6 + 7
= 40
Therefore, f(–3) = 40.
To find f(0) and f(2), follow the same process. Substitute 0 for x to find f(0), and substitute 2 for x to find f(2).