a 15 foot long standard weight pipe with a diameter of 4 inches is filled with water. what would be the total approximate weight of the pipe and the water it contains?

If I recall my non-metric units, 1 cubic foot of water weighs about 62.4 pounds.

the volume of the tube is pi(1/36)(15) cubic feet
= 1.309 cubic feet

so the weight of the water is 1.309 x 62.4 lbs
= 8.38 lbs.

I have no clue what a "standard weight" pipe would weigh, google it then add it on.

Assuming you are talking about "standard" steel Schedule 40 pipe, use the table found here:
http://www.engineeringtoolbox.com/ansi-steel-pipes-d_305.html
You will probably find that the pipe wall weighs more than the water inside.

oops, don't know what happened in this typo

1.309 x 62.4 lbs is 81.68 lbs of course.

thanks!

To calculate the total weight of the pipe and water it contains, you first need to find the weight of the water, which you correctly calculated to be 81.68 pounds.

To determine the weight of the pipe, you mentioned that it is a "standard weight" pipe. However, the weight of the pipe can vary depending on the material and specifications. In this case, you can use the table provided in the link (http://www.engineeringtoolbox.com/ansi-steel-pipes-d_305.html) to find the weight per foot of the standard steel Schedule 40 pipe.

Using the table, locate the appropriate size for a 4-inch diameter pipe, and the weight per foot will be specified. Multiply that weight per foot by the length of the pipe (15 feet) to find the weight of the pipe.

By adding the weight of the water (81.68 pounds) and the weight of the pipe, you can calculate the total approximate weight of the pipe and the water it contains.