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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Wednesday, August 8, 2007 at 4:39pm.

(x+3)(x-3)>0 answer: x<-3 or x>3

x^2-2x-15</=0 answer: -3</=x</=5

12x^2=3x answer: x=1/4

sin2x=sinx, 0</=x</=2pi answer: x=pi

lx-3l<7 answer: (-oo,oo)

(x+1)^2(x-2)+(x+1)(x-2)^2=0

answer: x=-1,2,1/2

27^(2x)=9^(x-3)answer: x=-3/2

logx+log(x-3)=1 answer: x=-2, 5

(x+3)(x-3)>0 answer: x<-3 or x>3

x^2-2x-15</=0 answer: -3</=x</=5

12x^2=3x answer: x=1/4

sin2x=sinx, 0</=x</=2pi answer: x=pi

no. recall that sin2x = 2(sinx)(cosx)

so

2(sinx)(cosx)-sinx=0

sinx(2cosx -1=0

sinx=0 or cosx=1/2

then x=0,pi,2pi from the first

or x = pi/3 (60º) or 5pi/3 (300º)

lx-3l<7 answer: (-oo,oo)

(x+1)^2(x-2)+(x+1)(x-2)^2=0

answer: x=-1,2,1/2

27^(2x)=9^(x-3)answer: x=-3/2

logx+log(x-3)=1 answer: x=-2,5

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