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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Wednesday, August 8, 2007 at 3:33pm.

1/(x+h) - 1/x= -h/(x^2+xh)

(2/x^2)/(10/x^5)= (x^3)/5

[1/(3+x) - 1/3]/x= -1/(9+3x)

2x/(x^2-6x+9) - 1/(x+1)- 8/(x^2-2x-3)= (x^2+15)/(x^3-5x^2+3x+9)

first 3 look ok

In the last one I would not have expanded the denominator, leave it as

(x+1)(x-3)^2

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