Homework Help: physics # 5

Posted by gomez on Tuesday, August 7, 2007 at 11:45pm.

5. The length of a simple pendulum with a period on Earth of one second is most nearly

a.) 0.12 m
b.) 0.25 m
c.) 0.50 m
d.) 1.0 m
e.) 10.0 m

The formula for the period is
P = 2 pi sqrt(L/g)
g is the acceleration of gravity, 9.8 m/s^2.
Solve for L. (or get out a piece of string and do the experiment.)

physics # 5 - kirafreedom, Saturday, March 30, 2013 at 9:18pm
Pendulum period in seconds
T ≈ 2π√(L/g)
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
Length for 1 second = 0.248 m
(b)

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