i have to write a balanced equation for the combustion of benzene..
C6H6 + O2 ==> CO2 + H2O
Answer: C6H6 + 14O2 --> 6C02 + 4H2O
Your answer is incorrect. There are more oxygen on the left, and more hydrogen on the right.
try coefficients 2,15,12,6
To write a balanced equation for the combustion of benzene, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's follow the steps to balance the equation:
Step 1: Write the unbalanced equation:
C6H6 + O2 → CO2 + H2O
Step 2: Balance the carbon atoms:
Since there are six carbon atoms on the left, we need six carbon dioxide (CO2) molecules on the right side:
C6H6 + O2 → 6CO2 + H2O
Step 3: Balance the hydrogen atoms:
Since there is only one hydrogen atom in each benzene molecule (C6H6), we need six water (H2O) molecules on the right side:
C6H6 + O2 → 6CO2 + 6H2O
Step 4: Balance the oxygen atoms:
Now let's balance the oxygen atoms. On the left side, we have O2, which means there are two oxygen atoms per molecule. Therefore, we need 3 O2 molecules on the left side:
C6H6 + 3O2 → 6CO2 + 6H2O
However, this equation is not fully balanced because we have 12 hydrogen atoms on the right side but only 6 on the left side. To balance the hydrogen atoms, we need to add a coefficient of 2 in front of the benzene (C6H6) on the left side:
2C6H6 + 15O2 → 12CO2 + 6H2O
So, the balanced equation for the combustion of benzene is:
2C6H6 + 15O2 → 12CO2 + 6H2O