Sunday

August 31, 2014

August 31, 2014

Posted by **Artie** on Saturday, August 4, 2007 at 1:38pm.

You have not provided enough information to answer that question. Besides, a different symbol should be used for the standard deviation and the variable (Z) itself. Are you sure there isn't a "sigmaZ", or something like that, in the statement of the standard deviation?

Oops! made a typing error. It should read: If Z is a standard normal variable, find the probability that Z lies between -1.10 and -0.36

See my answer in your repost of this question.

Thanks for asking.

Sorry, it is the same problem posed by John. Is that also you?

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