IF
f(x)={(3,5), (2,4), (1,7)}
What about 1/f(x)?
would is be {1/5, 1/4, 1/7}?
IF
g(x)=sqrt(x-3)
k(x)=x^2+5
how would I solve?
(k-g)(5)=
(g o k)(7)=
k^-1(x)=
(kg)(x)=
nevermind. I know how to do them.
It seems like you already know how to solve these questions. However, I can still provide assistance if you need further clarification.
In the first question, you are given a function f(x) with three points: (3,5), (2,4), and (1,7). To find 1/f(x), you can simply take the reciprocal of the y-values of the given points. So, you are correct that 1/f(x) would be {1/5, 1/4, 1/7}.
In the second set of questions, you have two functions: g(x) = sqrt(x-3) and k(x) = x^2+5.
If you want to evaluate (k-g)(5), it means you need to substitute x=5 into both functions and then subtract the results. So, you would calculate k(5) - g(5).
If you want to calculate (g o k)(7), it means you need to first substitute x=7 into k(x) and then take the result and substitute it into g(x). So, you would calculate g(k(7)).
For k^-1(x), it represents the inverse of the function k(x). To find the inverse, you can switch the roles of x and y and solve for y. So, you would rewrite k(x) as y = x^2+5 and then solve for x in terms of y.
For (kg)(x), it means you need to evaluate g(x) first and then take the result and substitute it into k(x). So, you would calculate k(g(x)).
If you have any specific questions or need further explanation, feel free to ask!