Wednesday

April 16, 2014

April 16, 2014

Posted by **Susan** on Thursday, August 2, 2007 at 7:52pm.

3 y^2 -7y - 6 = 0

When using the quadratic formaul to find y, a = 3, b = -7 and c = -6

y = [-b +/- sqrt (b^2 -4ac)]/2a

= {7 +/- sqrt (49 + 72)}/6

= {7 +/- 11)/6

= +3 or -2/3

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