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January 30, 2015

January 30, 2015

Posted by **Anonymous** on Thursday, August 2, 2007 at 3:47pm.

Can you see how n! = n(n-1)!?

or that (n+1)! = (n+1)n! ?

just like 8! = 8(7!)

then [3(n+1)!]/[5n!]

=3(n+1)n! / 5n!

=3(n+1)/5

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