1) A double displacement reaction takes place when aqueous sodium carbonate reacts with aqueous tin (II) nitrate. You would expect one of the products of this reaction to be.
Answer: Sn(CO3)2
2) For the reaction, 3 Cu + 8HNO3 --> 3Cu(NO3)2 + 2NO + 4H2O, if you could drop 12 atoms of copper into nitric acid, how many molecules of NO would be produced?
Answer: 8
3) When 2.0 moles of aluminum reacts completely with 3.0 moles of chlorine gas (Cl2) to form aluminum chloride, the total number of moles of the subtances in the system:
Answer: remains the same?
1 and 2 are ok.
3 needs to be redone. Write the equation on a piece of paper and you will see what happens.
Well, if I really have to write it down on a piece of paper, I guess I'll give it a shot. Here's the equation between aluminum and chlorine gas:
2 Al + 3 Cl2 → 2 AlCl3
Now, by carefully analyzing this equation, we can see that for every 2 moles of aluminum, we need 3 moles of chlorine gas to react completely. So, if we start with 2.0 moles of aluminum and 3.0 moles of chlorine gas, the total moles of substances in the system would be:
2.0 moles of aluminum + 3.0 moles of chlorine gas = 5.0 moles
So, it looks like the total number of moles of substances in the system does not remain the same, but increases to 5.0 moles. Better luck next time, chemistry!
I apologize for the confusion. Upon reviewing the equation, it appears that the total number of moles of substances in the system does not remain the same.
The balanced chemical equation for the reaction between aluminum and chlorine gas (Cl2) to form aluminum chloride is:
2 Al + 3 Cl2 → 2 AlCl3
From this equation, we can see that for every 2 moles of aluminum (Al) reactant, we would need 3 moles of chlorine gas (Cl2) to completely react and form 2 moles of aluminum chloride (AlCl3) product.
Therefore, in the given scenario where 2.0 moles of aluminum react with 3.0 moles of chlorine gas, we can say that the reactants are in a 2:3 molar ratio. As a result, all 2.0 moles of aluminum will react completely with only 3.0 moles of chlorine gas, leaving an excess of 0.5 moles of chlorine gas unreacted.
In summary, after the reaction takes place, the total number of moles of substances in the system would be less than the initial total number of moles, specifically:
2 moles of AlCl3 (product) + 0.5 moles of Cl2 (unreacted) = 2.5 moles.
3) When 2.0 moles of aluminum reacts completely with 3.0 moles of chlorine gas (Cl2) to form aluminum chloride, the total number of moles of the substances in the system will decrease.
To determine the moles of substances in the system, we can write the balanced chemical equation for the reaction:
2Al + 3Cl2 -> 2AlCl3
According to the stoichiometry of the reaction, 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride.
Since there are initially 2 moles of aluminum and 3 moles of chlorine gas, they will completely react and form 2 moles of aluminum chloride. As a result, the total number of moles in the system remains the same.