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April 18, 2015

April 18, 2015

Posted by **COFFEE** on Sunday, July 29, 2007 at 11:57pm.

.. my work so far. i used the ratio test

= lim (n-->infinity) | [((n+3)/(10^(n+1)))*((x-5)^(n+1))] / [((n+2)/(10^n))*((x-5)^n)] |

.. now my question is: was it ok for me to add "+1" to "n+2" to become "n+3"?

= lim (n-->infinity) | [((n+3)/(10^(n+1)))*(((x-5)^(n+1))/1)] * [((10^n)/(n+2))*(1/((x-5)^n))] |

= lim (n-->infinity) | [(((n+3)(x-5))/10)*(1/(n+2))] |

how do i finish this so that i could find the endpoints? please help. thank you.

- polser elmetary -
**roger**, Monday, September 29, 2008 at 6:22pmwhat is the answer x-5/3=10

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