Monday

December 22, 2014

December 22, 2014

Posted by **COFFEE** on Sunday, July 29, 2007 at 11:57pm.

.. my work so far. i used the ratio test

= lim (n-->infinity) | [((n+3)/(10^(n+1)))*((x-5)^(n+1))] / [((n+2)/(10^n))*((x-5)^n)] |

.. now my question is: was it ok for me to add "+1" to "n+2" to become "n+3"?

= lim (n-->infinity) | [((n+3)/(10^(n+1)))*(((x-5)^(n+1))/1)] * [((10^n)/(n+2))*(1/((x-5)^n))] |

= lim (n-->infinity) | [(((n+3)(x-5))/10)*(1/(n+2))] |

how do i finish this so that i could find the endpoints? please help. thank you.

- polser elmetary -
**roger**, Monday, September 29, 2008 at 6:22pmwhat is the answer x-5/3=10

**Answer this Question**

**Related Questions**

calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^...

calculus - ratio test - infinity of the summation n=1: (e^n)/(n!) [using the ...

calculus - ratio test - Posted by COFFEE on Sunday, July 29, 2007 at 6:32pm. ...

Calculus - ratio test - infinity of the summation n=1: (e^n)/(n!) [using the ...

Calculus 2 - In the following series x is a real number. In each case, use the ...

CALC - please help me...for the power series summation of n^4x^n/2(n-1)factorial...

CALC 2 - In the following series x is a real number. In each case, use the ratio...

CALC 2 pls help!! - In the following series x is a real number. In each case, ...

Calculus - How do I find the radius of convergence of a series where n=1 to ...

Calculus - I am maybe overthinking this, but what is the lim as n-> infinity ...