Adult tickets for a play cost $9 and child tickets cost $8. If there were 23 people at a performance and the theater collected $193 from ticket sales, how many children attended the play?

A = number of adults
C = number of children
Set up two equations.
A + C = 23
9A + 8C = 193

Solve the equations simultaneously to find A and C.

C=23-A

9A+8(23-A)=193
9A+184-8A=193
184+A=193
A=9

C=23-A
C=23-9
C=14

14 Children attended the play

Joe Keeps only $5-bills and $20-bills in his piggy bank. If he has 216bills that worth $2865, how many $5- bills are in the bank

The Jurassic Zoo charges ​$13


for each adult admission and ​$5

for each child. The total bill for the 152

people from a school trip was ​$1096
.
How many adults and how many children went to the​ zoo?  

To solve the equations simultaneously, we can use either substitution or elimination method. Let's use the elimination method in this case.

Start with the equations:
A + C = 23
9A + 8C = 193

Multiply the first equation by 8 to make the coefficients of C the same in both equations:
8A + 8C = 184

Now, subtract the modified first equation from the second equation to eliminate C:
(9A + 8C) - (8A + 8C) = 193 - 184
A = 9

Substitute A = 9 back into the first equation to solve for C:
9 + C = 23
C = 23 - 9
C = 14

Therefore, there were 14 children who attended the play.