Posted by **john** on Sunday, July 29, 2007 at 12:06pm.

Xan you please tell me how you find the rate of change of Y= the square root of X when Y is increasing at 2 units per second and X=1?

y= √x

you are given dy/dt = 2 units/sec when x=1

I assume you want dx/dt, that is, how fast is x changing at that moment.

from your equation

dy/dt = 1/(2√x)*dx/dt

when x=1, y =1 from your equation, and dy/dt=2 so sub it in

2 = 1/(2√1) * dx/dt and

dx/dt = 4 units/sec

## Answer This Question

## Related Questions

- Calculus - In a right triangle, the hypotenuse is of fixed length of 15 units, ...
- math - Resolved QuestionShow me another » AP Calculus related rates problem? The...
- Math(I Don't Get THIS!!) - 15sqrt8x^16/5sqrt2x^4 *I totally need help with this ...
- calculus - the side of squyare,s, is increasing at a rate of k unites per second...
- Calculus - A particle is moving along the curve y = 2 √{3 x + 7}. As the ...
- Calculus - A particle is moving along the curve y = 2 √{3 x + 7}. As the ...
- Calculus - A particle is moving along the curve y = 2 √{3 x + 7}. As the ...
- Calculus AB - The volume V or a cone (V = 1/3 π rČ h) is increasing at a ...
- Calculus: Implicit - so i suppose to find slope. i have trouble this problem. my...
- Math PLEASE HELP ASAP - -PLEASE INCLUDE SOLUTIONS AND EXPLAIN HOW YOU DID IT ...

More Related Questions