How do I solve for these?On a line,If M is the midpoint of segment AB, AM=4x and AB=7x+9. What is the value of MB?
I cannot figure this one out either:If B is between A and C, AB=5y+4, BC=7y-3, and AC=20y-7. Find the value of y, AB, BC, and AC.
Can someone please help me??
How do I solve for these?On a line,If M is the midpoint of segment AB, AM=4x and AB=7x+9. What is the value of MB?
If AM = 4x and AB = 7x + 9 then MB = AB - AM or 7x + 9 - 4x = ?
I cannot figure this one out either:If B is between A and C, AB=5y+4, BC=7y-3, and AC=20y-7. Find the value of y, AB, BC, and AC.
Can someone please help me??
AB + BC = AC. Substitute and solve for y, AB, BC and AC.
To solve for MB in the first question, you need to use the fact that M is the midpoint of segment AB. This means that the distance from A to M is equal to the distance from M to B.
Given that AM = 4x and AB = 7x + 9, you can set up an equation:
AM = MB
4x = MB
Then, substitute the value of AM into the equation:
4x = 7x + 9
To isolate x, you can subtract 7x from both sides:
4x - 7x = 9
Simplify:
-3x = 9
Now, divide both sides by -3 to solve for x:
x = -3
Finally, substitute x back into the equation for MB:
MB = 4x = 4(-3) = -12
So, the value of MB is -12.
Moving on to the second question, you are given the lengths of segments AB, BC, and AC and asked to find the value of y as well as the lengths of the segments.
Since B is between A and C, the sum of the lengths AB and BC should be equal to AC.
Therefore, you can set up an equation:
AB + BC = AC
Substitute the given lengths of AB, BC, and AC:
5y + 4 + 7y - 3 = 20y - 7
Combine like terms:
12y + 1 = 20y - 7
Subtract 12y from both sides:
1 = 8y - 7
Add 7 to both sides:
8 = 8y
Divide both sides by 8 to solve for y:
y = 1
Now that you have found the value of y, you can substitute it back into the equations for AB, BC, and AC to find their values.
AB = 5y + 4 = 5(1) + 4 = 5 + 4 = 9
BC = 7y - 3 = 7(1) - 3 = 7 - 3 = 4
AC = 20y - 7 = 20(1) - 7 = 20 - 7 = 13
So, the value of y is 1, and the lengths of AB, BC, and AC are 9, 4, and 13, respectively.