Posted by **anonymous** on Friday, July 27, 2007 at 2:15am.

evaluate h(-2/3) if h(x) = [[x-2]]

(-2/3)-2 = -2.666666667

is this the right correct?

If those are absolute value signs surrounding the x-2 on the right, then the answer is +2.666..= 8/3

why is it a positive 8/3 instead of a negative because you subtracted 2 from negative 2/3

As I said earlier, it looks like you might have absolute value signs (| |)around the

-8/3. That would make the final answer positive. If those are just brackets [ ] (which would serve no mathematical purpose here) then the answer would be -8/3.

## Answer this Question

## Related Questions

- algebra 2 - evaluate:-[a-3b],if a= -2 and b= 6 -[-2-18] -[20] 20 correct? these ...
- Algebra2 - Are these right?! Absolute value : 1. |x^2-2x+16|=8 x=-4 x=-3 x=-2 x=...
- Algebra2 - Making Sure these are right? absolute value: 1.|7x+2|=10 x=1.1 x=1.7 ...
- Algebra - Right now we are learning about absolute value inequalities. I have to...
- question - I the question "List all the numbers that have an absolut value of 12...
- Math - Given that x<5, rewrite 5x- (x-5) without using the absolute value ...
- math, help - For the following set, which number has the largest absolute value...
- math !!!!!!please part of a major grade!!!!!! - when in the absolute value of x ...
- Geometry MATH CHECK - Check? In your own words, explain why we use the formula ...
- Algebra 2 (check) - I have some problems that I've answered and I need someone ...