algebra 2
posted by erin .
evaluate:[a3b],if a= 2 and b= 6
[218]
[20]
20 correct? these are absolute bars by the way.
No, not correct. 20 is 20. Put a minus sign in front of it and you have 20. The error is made going from line 2 to line 3.
but absolute is never negative
There is a minus sign OUTSIDE of the absolute value signs. It reverses the sign of the absolute value term, making it negative.
an absolute value can never be negative

C+(c)=8