Monday

October 20, 2014

October 20, 2014

Posted by **Tammy** on Tuesday, July 24, 2007 at 7:12pm.

(x^(-3/5))

----------- divide

x ^ (1/5)

I know the problem then needs to look like this:

(x^(-3/5))(x^(-1/5))

(multiply the two above)

Then it needs to look like this:

(I can't write it though, so I'll tell you)

The 5th root out of (x^(-3)(x^(-1)

Then that adds up to the 5th root out of x^(-4)

and this is were I need help. To get rid of the fifth root there neeeds to be something to the power of 5 under the root symbol, but how do I get there? If my math to this point isn't correct, please correct it. I need Help!

The way you presented the problem indicates that you are simply dividing two powers.

the answer to that would be x^(-4/5)

There is nothing to "get rid of", because it is an expression

Unless you have this as part of an equation, where you would solve for x, you would be done.

Do you perhaps have a value of x which is to be substituted?

I think that the goal is to get rid of the 5th root in this case. I know that I have to make whatever is under or in the root -in this case the number is X equal some number to the fifth power.

I am supposed to use the rule

a^(m/n)= n

(the n-root) (don't know how to type it) and under the root symbol a^m

and the other rule is (a^x)(a^b)= a^(x+b)

The book calls this Radical Ecponents and Radical Expretions.

My problem is that it only says X, another problem I had, I can solve

(I will use ,- to symbolise the root)

to give you an idea on another problem how this is supposed to be solved

[y^ (-1/4)][y(3/4)] (multiply the two terms)

Following the rule

4,- [y^(-1)][y^3] (the for stands for the 4th root and the rest is under the root symbol)

using the rule of multiplication of the powers you then get

4,- y^2

which is the same as the following and keeping in mind that there has to be some number to the power of 4.

4,- (y^(1/2)^4)

The fours cancel and then you have y^ (1/2)

Note that (1/2)4 is the same thing as 2 so it's like factoring too.

I just can't do the problem I showed you. I hope I gave you enough info to help me out!!

Thanks you!

**Answer this Question**

**Related Questions**

Algebra - I think that the goal is to get rid of the 5th root in this case. I ...

Algebra - - 20> 8 +7a Solve inequalities like you would an equation, EXCEPT ...

algebra - Problem Two: 5/9 + (2/9)x = 25/7 + (6/7)x – 2/3 Multiply figures ...

math - 35 divided by [9 plus (9-7) minus 4] plus 10 times 3..can someone please ...

math - 35 divided by [9 plus (9-7) minus 4] plus 10 times 3..can someone please ...

math - kelly solved the following problem on her recent math test 121/11+4*8=120...

need guidance on an algebra problem - 20 x+3(y-1)=11 2(x-y)+8y = 28 multiply ...

algebra 2 - Would some one look at these problems and see if I got them right ...

algebra 2 - I am trying to factor the expression -8y^2+28y-60 but can't get an ...

Math - No, I'm sure the problem is written like this: [(3a^3-27a)/(2a^2+13a-7...