Writing this equation
posted by Katty .
how do I write the equation of a line perpendicular to the line 6x – 3y=10 and containing the point (-6, 2).
The line you are given can have its equation rewritten im y = mx + b as:
y = 2x - 10/3
That tells you that is slope is m = 2. A line that is perpendicular to that must have a slope of -1/2, because the product of slopes of perpendicular lines must be m = -1. (Trust me on that one, or check your textbook.)
A new perpendicular line going through a point (x*,y*) will have the equation
y - y* = m (x - x*)
y - 2 = (-1/2)(x -(-6))
y - 2 = -x/2 - 3
y = -(x/2) -1
(y - )/(
Ignore the last line of my last answer. It's some leftover garbage I neglected to delete