Posted by **Jim** on Tuesday, July 24, 2007 at 12:38pm.

Can someone show me how to solve this? Someone tried to explain it to me-I didn't get it.A line contains the points (3, -4) and (5, 2). Another line graphed in the same coordinate plane contains the points (0, 5) and (-2, -1). Based on the slopes of these lines are they parallel, perpendicular or neither?

The slope of any line from point 1 to point 2 is (y2-y1)/(x2-x1). Therefore the slopes of the two lines you are talkng about are

(2 -(-4))/(5-3) = 6/2 = 3

and

(-1 -(5)/(-2-0)= -6/-2 = 3

Thelines are therefore parallel because they have the same slope.

## Answer this Question

## Related Questions

- geomerty - A line contains the points (0, -2) and (1,3). Another line graphed in...
- Math - The graph of the equation y=4-x consists of all the points in the ...
- math - A tangent line is drawn to the hyerbola xy=c at a point P. 1) show that ...
- math repost!! - please help, i procrastinated and now this is due tomorrow!! A ...
- analytic geometry helps are appreciated - A line with slope 3 is 2 units away ...
- geometry - We are learning about proofs. We drew lines between noncollinear ...
- Math - 1.The square of x is equal to 4 times the square od y. If x is 1 more ...
- Geometry - In the standard (x,y) coordinate plane, if the x-coordinate of each ...
- geometry - Joey plots a point P on the line AB, as shown. Which statement is ...
- Geometry - Three points are on a coordinate plane: A(1, 5), B(-2, -4), and C(6...