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January 31, 2015

January 31, 2015

Posted by **Giselle** on Monday, July 23, 2007 at 6:44pm.

(A)None

(B)One

(C)Two

The average is defined this way:

average=1/5 (score1 + score2 + ...)

Here. We want to find the number n of folks that can get a 50 with a class average of 80.

80=1/5(n*50 + sum of other scores)

Now, to maximize n, we need to maximize the sum of the other scores, or

80=1/5(n*50 + 100*(5-n))

solve for n

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