Saturday
September 20, 2014

Homework Help: math, algebra II

Posted by student on Sunday, July 22, 2007 at 3:13pm.

Can someone explain to me step by step how the book got to this answer i want to understand the steps....thanks

Find the inverse, if it exists,for the matirx (*I used the underscore to separate the numbers within the matix)

-2_1_3
3_-1_2
-4_2_0

the answer is:

-4_6_5
-8_12_13
2_0_-1

The answer you supplied is really not the Inverse matrix since when you multiply the two you get
6 0 0
0 6 0
0 0 6 so each of the numbers in your answer should be divided by 6

There are several ways to find the inverse depending on your level of math knowledge.

Here is a rather straightforward way

let
│-2_1_3│ │a b c│ │1 0 0 │
│3_-1_2│ │d e f│=│0 1 0 │
│-4_2_0│ │g h i│ │0 0 1 │

from this we get
-2a + d + 3g = 1
3a - d + 2g = 0
-4a + 2d = 0

and
-2b + e + 3h = 0
3b - e + 2h = 1
-4b + 2e = 0

and
-2c + f + 3i = 0
3c - f + 2i = 0
-4c + 2f = 1

this gives you 3 systems of 3 equations in 3 variables to solve which do not appear to be that difficult.
Let me know what you got.
(Also check my math, I did not check it)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

math help - Can someone explain to me the following step by step , i 've looked ...
Algebra help - f(x)=x^3-4x^2-x+4 How do I find the x-intercept for this? This is...
math ergent please please... - 10.a)Solve the inequality x^3-5x^2+2x+8<0 by i...
Algebra II (Matrices) - My book doesn't solve it like a linear equation, they ...
Algebra 1--Step-by-Step - Can someone show me how to solve these step-by-step? ...
Calculus - 1/a+1 + 1/a-1 I solved this out by multiplying the (a+1) by (a-1) and...
Latin - Can someone help me to understand the step by step process of the five ...
Math - How do you work this problem step by step? p-12 when p= 22 We don't know ...
Math / Linear Equations - I was looking on a website that teaches linear algebra...
chemistry clearly step by step - Al2(s04)3 solution of 1 molal concentration is ...

Search
Members