Tuesday

March 3, 2015

March 3, 2015

Posted by **Candi** on Friday, July 20, 2007 at 2:00am.

The price p, in dollars, and the quantity x sold of a certain product obey the demand equation

x = -5p + 100, 0 (less than or equal to) p (less than or equal to) 20

a.) Express the revenue R as a funtion of x.

b.) What is the revenue if 15 units are sold?

c.) What quantity x maximizes revenue? What is the maximum revenue?

d.) What price should the company charge to maximize revenue?

Revenue= P*x

but p= 1/5 x +20 check that, then substitute to find Revenue as a function of x.

Maximizing Revenue. In calculus, there is a very elegant way. In algebra, we want find when Revenue is max.

Revenue= P*x

but p= 1/5 x +20 check that, then substitute to find Revenue as a function of x.

Maximizing Revenue. In calculus, there is a very elegant way. In algebra, we want find when Revenue is max.

- college algebra -
**Anonymous**, Monday, March 2, 2015 at 11:49pmThe revenue function for a bicycle shop is given by R(x) = x · p(x) dollars where x is the number of units sold and p(x) = 100 − 0.5x is the unit price. Find the maximum revenue.

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