Posted by **Amy** on Thursday, July 19, 2007 at 4:24pm.

Can someone please explain how to do this problem? I am really confused. Thank you.

3. How much heat does 32.0 grams of water absorb when it is heated from 25.0 degrees Celsius to 80.0 degrees Celsius?

q = mass*specific heat water*(Tfinal-Tinitial) = ??.

mass is 32.0 g

Tfinal = 80.0

Tinitial = 25.0

You need to look up the specific heat of water and plug in the numbers. Solve for q. Post your work if you get stuck.

q = 32.0g (55.0)

q = 1760

So does q equal 1760

You haven't multiplied by the specific heat of water, or did you? And if so what are the units of your answer.

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