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March 31, 2015

March 31, 2015

Posted by **Anonymous** on Thursday, July 19, 2007 at 1:20pm.

a. 64

b. 98

c. 112

d. 128

e. 224

I worked out the problem (8 cpr 4), and I got 70. As you can see, it is not of the answer choices.

Why would you try 8C4?

Four teams cannot play together in one game.

The number of possible games in one round would be 8C2 which is 28.

According to your wording each of those games would be repeated 4 times which would result in 112, one of the choices.

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