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March 1, 2015

March 1, 2015

Posted by **Scott** on Thursday, July 19, 2007 at 9:59am.

Ok now I'm trying to figure out the distance formula.

the coordinates are (-1,3) and (2,5)

So I take (5-3)^2 + (2-1)^2

and get 2^2 + 1^2.

so 4 + 1 is 5. so the square root of 5 is the answer?

your second subtraction is wrong

it should be (2-(-1)^2 which is 3^2

so you should have

distance =√(2^2 + 3^2)

=√13

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