Posted by **lana** on Wednesday, July 18, 2007 at 10:57am.

Hi i posted this question:

the general expression for consecutive multiples of 6 is 6N, 6(N + 1), 6(N +2), etc. find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12.

and than Bobpursley replied:

Let N be the first, so n+1 is next, etc.

4(6(n+1))-2(6(n+3))=12

so, find n, then 6(n+1) for the first, 6(n+2) for the second, and 6(n+3) for the third.

So now i don't understand what he means by that. help me out here

Did you solve for n?

If you did, then you need three consecutive numbers divisible by six. They will be:

6(n+1) is the first number.

6(n+2) will be the second number.

You figure out what the third number will be.

## Answer This Question

## Related Questions

- algebra 2 - the general expression for consecutive multiples of 6 is 6N, 6(N + 1...
- Algebra II - One half of the sum of three consecutive multiples of 10 is 90. ...
- statistics - The mean of 3 consecutive multiples of 3 is equal to A.The mean of ...
- math - The sum of three consecutive multiples of 7 is zero.find the integers
- algebra - Show a complete algebraic solution for the following: find 4 ...
- quad. eq. - find 3 consecutive integers such that the product of the second and ...
- MATHS - The sum of three consecutive multiples of 3 is 36. The smallest of the ...
- algebra - Find the two consecutive odd integers such that 5 times the first ...
- Pre-Algebra - Find two consecutive odd integers such that 5 times the first ...
- Algebra - The length in feet of three ropes are consecutive multiples of three. ...

More Related Questions