Homework Help: algebra 2

Posted by lana on Tuesday, July 17, 2007 at 1:19pm.

the general expression for consecutive multiples of 6 is 6N, 6(N + 1), 6(N +2), etc. find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12.

Let N be the first, so n+1 is next, etc.

4(6(n+1))-2(6(n+3))=12

so, find n, then 6(n+1) for the first, 6(n+2) for the second, and 6(n+3) for the third.

i dont understand what you mean by that

What's some things I'll need for this class?

No one has answered this question yet.

Answer this Question

Related Questions

algebra 2 - Hi i posted this question: the general expression for consecutive ...
Algebra II - One half of the sum of three consecutive multiples of 10 is 90. ...
statistics - The mean of 3 consecutive multiples of 3 is equal to A.The mean of ...
math - The sum of three consecutive multiples of 7 is zero.find the integers
MATHS - The sum of three consecutive multiples of 3 is 36. The smallest of the ...
algebra - Show a complete algebraic solution for the following: find 4 ...
quad. eq. - find 3 consecutive integers such that the product of the second and ...
math - the 2 consecutive multiples of 6 up to 116
math - The sum of four consecutive multiples of 5 is 230. What is the greatest ...
math - there are three consecutive positive integers such that the sum of the ...

For Further Reading

First Name:
School Subject:
Answer: