posted by lana .
the general expression for consecutive multiples of 6 is 6N, 6(N + 1), 6(N +2), etc. find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12.
Let N be the first, so n+1 is next, etc.
so, find n, then 6(n+1) for the first, 6(n+2) for the second, and 6(n+3) for the third.
i don't understand what you mean by that
What's some things I'll need for this class?