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October 31, 2014

October 31, 2014

Posted by **aziiancaligirl** on Sunday, July 15, 2007 at 11:51pm.

Let's use cos 2A = 1 - 2sin

and we can match

cos x = 1 - 2sin

so we will need cos x

we know sin x = -.4 and x is in the fourth quadrant, so the cosine will be positive.

Drawing a right angled triangle with side 2 and hypotenuse 5 ( .4 = 4/10 = 2/5), and using Pythagoras it is easy to see that cos x = √21/5

then:

√21/5 = 1 - 2sin

.

.

.

.

I got sin (x/2) = √(5-√21)/√10 or appr.2043

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