Wednesday
September 17, 2014

Homework Help: algebra

Posted by carla on Saturday, July 14, 2007 at 7:12am.

Find two consecutive positive integers such that the sum of their squares is 85.

n^2+(n+1)^2+2n = 85
n^2+n^2+2n+1=85
2n^2+2n=84
n^2+n=42
n^2+n-42=0
(n-6)(n+7)=0
n=6
n=-7

Is my work and answer correct?


-7 is not a positive integer. Your first equation is wrong, because the 2n term should not be there. Your second equation is correct, and after that you correectly solve for n. Since they ask for postive integer solutions only, the only number that fits, for n, is 6. The second integer will by definition be n+1, which is 7.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

math, algebra - 2a+2ab+2b I need a lot of help in this one. it says find two ...
math - there are three consecutive positive integers such that the sum of the ...
Algebra - The difference of the cubes of two consecutive odd positive integers ...
Algebra - The difference of the cubes of two consecutive odd positive integers ...
algebra! - The difference of the cubes of two consecutive odd positive integers ...
Algebra - The difference of the cubes of two consecutive odd positive integers ...
Algebra - The sum of the squares of two consecutive positive even integers is ...
math - The difference of the cubes of two consecutive odd positive integers is ...
Algebra - Find two consecutive positive integers such that the sum of the square...
math - The sum of the squares of two positive consecutive is 41. Find the ...

Search
Members