Posted by **carla** on Saturday, July 14, 2007 at 6:53am.

I worked the problem out, but could you check my work over and see if it's correct? I used the quadratic formula.

2x^2+10x+11

a=2 b=10 c=11

x=-10(plus or minus) sqrt 10^2-4(2)(11)

over 2(2)

-10(plus or minus) sqrt 100 - 8(11)

over 4

-10(plus or minus) sqrt 100-88

over 4

-10(plus or minus) sqrt 12

over 4

FINAL ANSWER:

-10(plus or minus) 2 sqrt 3

over 4

can this be simplified any more? or is the final answer even correct? pls help!!

Divide the 2a out, so

x= -2.5 +- .5* sqrt3

I'm a little confused. could you show me where exactly I went wrong? thanks! :)

When you used the formula

x = [-b +/- sqrt (b^2-4ac)]/2a, you forgot to divided by 2a, which is 4.

- algebra -
**crystal**, Tuesday, May 12, 2015 at 4:37pm
f

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