Posted by **student** on Friday, July 13, 2007 at 7:46pm.

Find expected value for the random variable.

its suppost to be a table 6 X 2 i used the .... to represent separation

z.....3......6.....9.....12.......15

p(z)..0.14..0.29..0.36..0.11...0.10

So what i did is i said

e(x) = 3 (0.14)+ 6(0.29)+ etc to all the rest. and my result was 8.22 am i correct that would be the expected value for the reandom variable.

## Answer this Question

## Related Questions

- Elementary statistics - Nine apples, four of which are rotten, are in a ...
- stats - Consider an infinite population with 25% of the elements having the ...
- math 3 - A bag contains 4 yellow, 2 red, and 6 green marbles. Two marbles are ...
- Stats - Y is a discrete random variable. The table below reports the values of Y...
- Statistics - x is a random variable with the probability function: f(X) = x/6 ...
- Intro to probability - Two balanced coins are tossed. What are the expected ...
- math - A jar contains 8 pennies, 3 nickels and 4 dimes. A child selects 2 coins ...
- Math - What is the probability that the random variable has a value between 0.1 ...
- Probability - The joint PMF, pX,Y(x,y), of the random variables X and Y is given...
- English - Can you please tell me if these sentences should be evaluated as ...

More Related Questions