Posted by COFFEE on Friday, July 13, 2007 at 4:36pm.
Please check my work below and comment.
A tank initially contains 80 gallons of fresh water. A 10% acid solution flows into the tank at the rate of 3 gallons per minute. The well-stirred mixture flows out of the tank at the rate of 3 gallons per minute. Find the amount of acid in the tank at the end of any time t. How much acid will be in the tank in 30 minutes? What will be the concentration (%) of acid in the tank after 30 minutes?
solution=0.3 gallons acid + 2.7 gallons H20
dy/dt = (rate in) - (rate out)
rate in = (0.3)(3) = 0.9 gallons/min
<-would this be gallons per min?
rate out = ((y(t))/80) * 3 gal/min
rate out = y(t)/(80/3)
Seperate into two intergrals:
-ln|(773/30)-y| = 3t/80+C, C=-ln|773/30|
-ln|(773/30)-y|=3t/80 - ln|773/30|
Is this the correct equation?
Then at 30 minutes, y(30) would be 17.4 gallons acid
Percentage after 30 minutes=17.4/80
correct procedure, however, one question: how did you get rate in .3*3? Wasn't it ten percent?
ah yes. Thank you!
Answer this Question
math - A tank contains 50 gallons of a solution composed of 90% water and 10% ...
math - Water is Pumped into an underground tank at a constant rate of 8 gallons ...
calculus - Water is Pumped into an underground tank at a constant rate of 8 ...
chemical calculations - Brine from a first tank runs into a second tank at 2 ...
math - An inverted square pyramid has a height equal to 8m and a top edge to 3m...
maths - 1)a linear function is represented by f(x)=2x+7 which of the following ...
calculus - A water heater in the shape of a circular cylinder is standing ...
Grenada - John has a 25-gallon fish tank. John filled his tank today with 23-...
Math - Beginning with a tank containing 8075 gallons of gasoline, more gas is ...
Calculus - A large tank is filled with 200 gallons of pure water. Brine ...